Use Fe = 56, S = 32, O = 16. When FeSO4 is oxidised to Fe2(SO4)3 in acidic solution, its equivalent mass is:

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Use Fe = 56, S = 32, O = 16. When $FeSO X_{4}$ is oxidised to $Fe X_{2} (SO X_{4}) X_{3}$ in acidic solution, its equivalent mass is:

Each

Fe X^{2 +}

loses one electron, so

n = 1

and equivalent mass equals molar mass

= 56 + 32 + 64 = 152