Use K = 39, Cr = 52, O = 16. The equivalent mass of K2Cr2O7 when it acts as an oxidant in acidic medium (product Cr^3+) is:

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Use K = 39, Cr = 52, O = 16. The equivalent mass of $K X_{2} Cr X_{2} O X_{7}$ when it acts as an oxidant in acidic medium (product $Cr X^{3 +}$ ) is:

Two Cr atoms go from +6 to +3, so

n = 6

. Equivalent mass

= 294/6 = 49