Molar volume at STP is 22.4 L/mol. Excess acidified KMnO4 oxidises 0.1 mol of oxalate, C2O4^2-, completely to CO2. The volume of CO2 produced at STP is:

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Molar volume at STP is $22.4 L/mol$ . Excess acidified $KMnO X_{4}$ oxidises $0.1$ mol of oxalate, $C X_{2} O X_{4} X^{2 -}$ , completely to $CO X_{2}$ . The volume of $CO X_{2}$ produced at STP is:

Each

C X_{2} O X_{4} X^{2 -}

gives 2

CO X_{2}

(

C X_{2} O X_{4} X^{2 -} 2 CO X_{2} + 2 e X^{-}

), so

0.1 \times 2 = 0.2

mol

CO X_{2}

. Volume

= 0.2 \times 22.4 = 4.48 L