In alkaline medium KMnO4 is reduced to MnO2. Taking molar mass of KMnO4 as 158 g/mol (K 39, Mn 55, O 16), find its equivalent mass in this reaction. Give the answer in g/eq to two decimal places.

JEE Main levelNumerical answerDifficulty 2 of 3rx076

In alkaline medium $KMnO X_{4}$ is reduced to $MnO X_{2}$ . Taking molar mass of $KMnO X_{4}$ as 158 g/mol (K 39, Mn 55, O 16), find its equivalent mass in this reaction. Give the answer in g/eq to two decimal places.

Numerical answer type, answer in g/eq, tolerance 0.02.

Mn goes from +7 to +4, so n-factor = 3. Equivalent mass = molar mass / n-factor = 158/3 = 52.67 g/eq.