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JEE Main levelSingle correct optionDifficulty 2 of 3rg102

For a gas at a given temperature the second virial coefficient is $B = + 25 mL mo l^{- 1}$ . Which conclusion is correct?

AThe gas is below its Boyle temperature and $Z$ is less than 1 at low pressure
BThe gas is above its Boyle temperature and $Z$ is greater than 1 at low pressure
CThe gas is at its Boyle temperature
DThe gas is below its critical temperature

Answer: B

Z \approx 1 + B / V_{m}

. A positive

B

gives

Z

greater than 1, meaning repulsive (excluded volume) effects dominate.

B

is positive only above the Boyle temperature, where

b

exceeds

a / RT

. Nothing can be said about

T_{c}

from this alone, but

T_{B}

is always above

T_{c}

, so being above

T_{B}

means being above

T_{c}

too; option D is therefore wrong.

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