JEE Advanced levelSingle correct optionDifficulty 3 of 3rg055
A gas is at its Boyle temperature. Which of the following is the best approximation for Z at molar volume Vm, retaining the lowest non-vanishing correction, for a van der Waals gas?
AZ=1−RTVma
BZ=1+Vmb
CZ=1+Vm2b2
DZ=1 exactly
Answer: C
At TB the second virial coefficient B=b−a/RT is zero, so the 1/Vm term disappears. The next term is C/Vm2 with C=b2 for a van der Waals gas, giving Z≈1+b2/Vm2, a small positive deviation.