For a gas at 300 K the second virial coefficient is B = -45.0 mL mol^-1. Using Z = 1 + (BP)/(RT) and R = 0.0821 L atm K^-1 mol^-1, the compressibility factor at 12.0 atm (three decimals) is

JEE Main levelNumerical answerDifficulty 2 of 3rg103

For a gas at $300 K$ the second virial coefficient is $B = - 45.0 mL mo l^{- 1}$ . Using $Z = 1 + \frac{BP}{RT}$ and $R = 0.0821 L atm K^{- 1} mo l^{- 1}$ , the compressibility factor at $12.0 atm$ (three decimals) is

Numerical answer type, tolerance 0.002.

Z = 1 + \frac{BP}{RT} = 1 + \frac{( - 0.0450 ) ( 12.0 )}{0.0821 \times 300} = 1 - \frac{0.540}{24.63} = 1 - 0.02192 = 0.97808

, i.e.

0.978