3.4 g of NH3 (M=17) reacts completely with excess oxygen: 4NH3 + 5O2 -> 4NO + 6H2O (N=14, O=16, H=1). Which statements are correct? Use 22.4 L/mol at STP.

NO formed occupies 2.24 L at STP

JEE Main levelOne or more correct optionsDifficulty 2 of 3mc135

3.4 g of $NH X_{3}$ ( $M = 17$ ) reacts completely with excess oxygen: $4 NH X_{3} + 5 O X_{2} 4 NO + 6 H X_{2} O$ ( $N = 14$ , $O = 16$ , $H = 1$ ). Which statements are correct? Use 22.4 L/mol at STP.

Moles of

NH X_{3}

= 0.2.

O X_{2}

= 0.2 x 5/4 = 0.25 mol = 8.0 g (true).

NO

= 0.2 mol = 6.0 g (true).

H X_{2} O

= 0.2 x 6/4 = 0.3 mol = 5.4 g, so 3.6 g is false.

NO

volume = 0.2 x 22.4 = 4.48 L, so 2.24 L is false.