For 2H2 + O2 -> 2H2O, 2 mol of H2 is mixed with 1.5 mol of O2 and the reaction goes to completion. The mass of water formed is (H=1, O=16)

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For $2 H X_{2} + O X_{2} 2 H X_{2} O$ , 2 mol of $H X_{2}$ is mixed with 1.5 mol of $O X_{2}$ and the reaction goes to completion. The mass of water formed is ( $H = 1$ , $O = 16$ )

2 mol

H X_{2}

needs only 1 mol

O X_{2}

, so

H X_{2}

is limiting and

O X_{2}

is in excess. Water formed = 2 mol = 2 x 18 = 36 g. Using

O X_{2}

as the basis wrongly gives 54 g.