In N2 + 3H2 -> 2NH3, what mass of NH3 is formed from 14 g of N2 with excess H2? (N=14, H=1)

NEET levelSingle correct optionDifficulty 1 of 3mc115

In $N X_{2} + 3 H X_{2} 2 NH X_{3}$ , what mass of $NH X_{3}$ is formed from 14 g of $N X_{2}$ with excess $H X_{2}$ ? ( $N = 14$ , $H = 1$ )

Moles of

N X_{2}

= 14/28 = 0.5. By the equation 1 mol

N X_{2}

gives 2 mol

NH X_{3}

, so 1.0 mol

NH X_{3}

forms. Mass = 1.0 x 17 = 17 g.