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Calcium carbonate decomposes as . The volume of at STP obtained from 25 g of () is

  1. A
  2. B
  3. C
  4. D

Answer: D

Moles of = 25/100 = 0.25, which gives 0.25 mol . Volume = 0.25 x 22.4 = 5.6 L at STP.
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