Answer: A, B, C
n(KMnOX4)=31.6/158=0.20 mol, giving 0.10 mol OX2 (2.24 L, 3.2 g). Residue =31.6−3.2=28.4 g. It contains 0.10 mol each of KX2MnOX4 (197 g/mol, 19.7 g) and MnOX2 (87 g/mol, 8.7 g). Mass fraction of KX2MnOX4 =19.7/28.4=69.4%, not 50%.