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Mole, molar mass, Avogadro number and molar volume
NEET level
Single correct option
Difficulty 1 of 3
mc114
The molar mass of
CuSO
X
4
⋅
5
H
X
2
O
is (Cu = 63.5, S = 32, O = 16, H = 1; in
g
mo
l
−
1
)
A
159.5
B
267.5
C
231.5
D
249.5
Answer: D
M = 63.5 + 32 + 4(16) + 5(18) = 63.5 + 32 + 64 + 90 = 249.5. Anhydrous
CuSO
X
4
is 159.5; counting 4 or 6 water molecules gives 231.5 or 267.5.
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