The total number of atoms in 0.5 mol of ammonia, NH3, is (take N_A = 6.02x10^23 mol^-1)

NEET levelSingle correct optionDifficulty 1 of 3mc113

The total number of atoms in 0.5 mol of ammonia, $NH X_{3}$ , is (take $N_{A} = 6.02 \times 1 0^{23} mo l^{- 1}$ )

One

NH X_{3}

molecule has 4 atoms (1 N + 3 H). Atoms = 0.5 x 4 x

N_{A}

= 2 x 6.02e23 = 1.204e+24. 3.01e+23 is the number of molecules only.

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