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Mole, molar mass, Avogadro number and molar volume
NEET level
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Difficulty 1 of 3
mc112
What is the mass of 6.72 L of methane (
CH
X
4
,
M
=
16
g
mo
l
−
1
) measured at STP? Use 22.4 L/mol at STP.
A
9.6
g
B
0.42
g
C
4.8
g
D
107.5
g
Answer: C
Moles = 6.72/22.4 = 0.3 mol. Mass = moles x molar mass = 0.3 x 16 = 4.8 g.
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