JEE Main levelSingle correct optionDifficulty 2 of 3mc123
A gas mixture contains 4.4 g of COX2 and 2.8 g of NX2 (C=12, N=14, O=16). Its volume at STP is
A4.48L
B2.24L
C3.67L
D5.76L
Answer: A
Moles of COX2 = 4.4/44 = 0.1; moles of NX2 = 2.8/28 = 0.1; total 0.2 mol. Volume = 0.2 x 22.4 = 4.48 L. Volumes of ideal gases at the same T and p simply add.