JEE Advanced levelOne or more correct optionsDifficulty 3 of 3ie220
Ksp of CaFX2 is 3.2×10−11. Neglect s relative to the added ion concentration where appropriate. Choose the correct statement(s).
ASolubility in 0.01MNaF is 3.2×10−7M
BSolubility in 0.01MCaClX2 is 2.8×10−5M
CSolubility in 0.01MNaF is greater than in 0.01MCaClX2
DSolubility in pure water is 2.0×10−4M
Answer: A, B, D
In pure water s=(Ksp/4)1/3=2.0×10−4M. In 0.01MNaF, s=Ksp/(0.01)2=3.2×10−7M. In 0.01MCaClX2, s=Ksp/(4×0.01)=2.8×10−5M, which is larger than the NaF value because fluoride enters squared.