A salt AB (1:1 type) has molar solubility 2.0 x 10^-5 mol L^-1. Its solubility product is

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A salt $AB$ (1:1 type) has molar solubility $2.0 \times 1 0^{- 5} mol L^{- 1}$ . Its solubility product is

For

AB A X^{+} + B X^{-}

[A X^{+}] = [B X^{-}] = s

, so

K_{s p} = s^{2} = (2.0 \times 1 0^{- 5})^{2} = 4.0 \times 1 0^{- 10}