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Ionic Equilibrium I
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Solubility product and simple solubility calculations
NEET level
Single correct option
Difficulty 1 of 3
ie175
The solubility of
CaSO
X
4
(molar mass
136
g
mo
l
−
1
) is
0.68
g
L
−
1
. Its
K
s
p
is
A
2.5
×
1
0
−
5
B
5.0
×
1
0
−
3
C
5.0
×
1
0
−
7
D
4.6
×
1
0
−
1
Answer: A
Molar solubility
s
=
0.68/136
=
5.0
×
1
0
−
3
M
. For a 1:1 salt
K
s
p
=
s
2
=
(
5.0
×
1
0
−
3
)
2
=
2.5
×
1
0
−
5
.
Practice Ionic Equilibrium I
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