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Ionic Equilibrium I
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Solubility product and simple solubility calculations
NEET level
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Difficulty 1 of 3
ie167
The solubility product of
AgCl
is
1.8
×
1
0
−
10
at 298 K. Its molar solubility in pure water (in
mol
L
−
1
) is closest to
A
1.3
×
1
0
−
5
M
B
1.8
×
1
0
−
10
M
C
9.0
×
1
0
−
11
M
D
6.7
×
1
0
−
6
M
Answer: A
For a 1:1 salt
K
s
p
=
s
2
, so
s
=
K
s
p
=
1.8
×
1
0
−
10
=
1.3
×
1
0
−
5
M
.
Practice Ionic Equilibrium I
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