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NEET levelSingle correct optionDifficulty 1 of 3ie166

Which expression gives the solubility product of $Ca X_{3} (PO X_{4}) X_{2}$ ?

A $K_{s p} = [Ca X^{2 +}]^{2} [PO X_{4} X^{3 -}]^{3}$
B $K_{s p} = [Ca X^{2 +}]^{3} [PO X_{4} X^{3 -}]^{2}$
C $K_{s p} = [Ca X^{2 +}]^{3} [PO X_{4} X^{3 -}]^{3}$
D $K_{s p} = 3 [Ca X^{2 +}] [PO X_{4} X^{3 -}] \times 2$

Answer: B

The salt dissociates as

Ca X_{3} (PO X_{4}) X_{2} 3 Ca X^{2 +} + 2 PO X_{4} X^{3 -}

. Each ion concentration is raised to its stoichiometric coefficient, so

K_{s p} = [Ca X^{2 +}]^{3} [PO X_{4} X^{3 -}]^{2}

.

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