A saturated solution of Ag2CrO4 has molar solubility 1.3 x 10^-4 mol L^-1. Its K_sp is

JEE Main levelSingle correct optionDifficulty 2 of 3ie177

A saturated solution of $Ag X_{2} CrO X_{4}$ has molar solubility $1.3 \times 1 0^{- 4} mol L^{- 1}$ . Its $K_{s p}$ is

Ag X_{2} CrO X_{4} 2 Ag X^{+} + CrO X_{4} X^{2 -}

gives

[Ag X^{+}] = 2 s

and

[CrO X_{4} X^{2 -}] = s

, so

K_{s p} = (2 s)^{2} s = 4 s^{3} = 4 (1.3 \times 1 0^{- 4})^{3} = 8.8 \times 1 0^{- 12}