MolSynapse
question bank
All chapters
NEET
JEE
Practice
MolSynapse
/
Question bank
/
Ionic Equilibrium I
/
Buffer solutions and Henderson equation
JEE Main level
Single correct option
Difficulty 2 of 3
ie124
A solution contains 0.30 M
NH
X
3
and 0.15 M
NH
X
4
Cl
. Given
p
K
b
(
NH
X
3
)
=
4.74
,
lo
g
2
=
0.301
and
p
K
w
=
14
, its pH is
A
9.56
B
8.96
C
4.44
D
9.26
Answer: A
pOH =
4.74
+
lo
g
(
0.15/0.30
)
=
4.74
−
0.301
=
4.439
, so pH =
14
−
4.439
=
9.56
.
Practice Ionic Equilibrium I
More on Buffer solutions and Henderson equation
Previous question
Next question
More questions on Buffer solutions and Henderson equation
Which of the following is NOT a buffer solution?
NEET level
50 mL of 0.2 M weak acid HA (pK_a = 4.70) is mixed with 50 mL of 0.1 M NaA. Use log 2 = 0.301. The pH of the mixture is
JEE Main level
To 1 L of a buffer containing 0.10 M CH3COOH and 0.10 M CH3COONa (pK_a = 4.74), 0.01 mol of solid NaOH is added (no volume change). The new ...
JEE Main level
For an acetic acid - acetate buffer (pK_a = 4.74), the ratio [CH3COO-]/[CH3COOH] needed for pH = 5.04 is (use log 2 = 0.301)
JEE Main level
100 mL of 0.30 M CH3COOH is mixed with 100 mL of 0.10 M NaOH. With pK_a = 4.74 and log 2 = 0.301, the pH is
JEE Main level
Sodium acetate (molar mass 82 g/mol) is to be dissolved in 1.0 L of 0.10 M acetic acid so that the pH is pK_a + 0.477 (log 3 = 0.477). The m...
JEE Main level