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Ionic Equilibrium I
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Buffer solutions and Henderson equation
JEE Main level
Single correct option
Difficulty 2 of 3
ie126
100 mL of 0.30 M
CH
X
3
COOH
is mixed with 100 mL of 0.10 M NaOH. With
p
K
a
=
4.74
and
lo
g
2
=
0.301
, the pH is
A
4.74
B
5.04
C
4.44
D
2.87
Answer: C
Acetic acid = 30 mmol, NaOH = 10 mmol. After reaction acid = 20 mmol, acetate = 10 mmol. pH =
4.74
+
lo
g
(
10/20
)
=
4.74
−
0.301
=
4.439
i.e. 4.44.
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