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JEE Main levelSingle correct optionDifficulty 2 of 3ie127

Sodium acetate (molar mass 82 g/mol) is to be dissolved in 1.0 L of 0.10 M acetic acid so that the pH is $p K_{a} + 0.477$ ( $lo g 3 = 0.477$ ). The mass of sodium acetate required (ignore volume change) is

A8.2 g
B24.6 g
C2.7 g
D82.0 g

Answer: B

pH

- p K_{a} = 0.477 = lo g 3

, so salt/acid = 3. Salt =

3 \times 0.10 = 0.30

mol, mass =

0.30 \times 82 = 24.6

g.

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