To 1 L of a buffer containing 0.10 M CH3COOH and 0.10 M CH3COONa (pK_a = 4.74), 0.01 mol of solid NaOH is added (no volume change). The new pH is

JEE Main levelSingle correct optionDifficulty 2 of 3ie123

To 1 L of a buffer containing 0.10 M $CH X_{3} COOH$ and 0.10 M $CH X_{3} COONa$ ( $p K_{a} = 4.74$ ), 0.01 mol of solid NaOH is added (no volume change). The new pH is

NaOH converts acid to salt: acid = 0.09 mol, salt = 0.11 mol. pH =

4.74 + lo g (0.11/0.09) = 4.74 + 0.087 = 4.83