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JEE Main levelSingle correct optionDifficulty 2 of 3ie122

50 mL of 0.2 M weak acid HA ( $p K_{a} = 4.70$ ) is mixed with 50 mL of 0.1 M NaA. Use $lo g 2 = 0.301$ . The pH of the mixture is

A5.00
B4.70
C4.40
D4.10

Answer: C

Moles: HA = 10 mmol, A

^{-}

= 5 mmol (same total volume, so ratio of moles = ratio of concentrations). pH =

4.70 + lo g (5/10) = 4.70 - 0.301 = 4.40

.

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