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JEE Main levelNumerical answerDifficulty 2 of 3ig190

The translational kinetic energy of $1 mol$ of an ideal gas at $400 K$ , taking $R = 8.314 J K^{- 1} mo l^{- 1}$ , in kJ (two decimals) is

Numerical answer type, answer in kJ, tolerance 0.01.

Answer: 4.99 kJ

K E = \frac{3}{2} RT = 1.5 \times 8.314 \times 400 = 4988.4 J = 4.99 kJ

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