A 5.0 L vessel at 273 K contains 1.0 g H2, 8.0 g O2 and 7.0 g N2. Taking R = 0.0821 L atm K^-1 mol^-1, the total pressure in atm (two decimals) is

JEE Main levelNumerical answerDifficulty 2 of 3ig191

A $5.0 L$ vessel at $273 K$ contains $1.0 g$ $H X_{2}$ , $8.0 g$ $O X_{2}$ and $7.0 g$ $N X_{2}$ . Taking $R = 0.0821 L atm K^{- 1} mo l^{- 1}$ , the total pressure in atm (two decimals) is

Numerical answer type, answer in atm, tolerance 0.02.

Moles:

H X_{2}

0.50

O X_{2}

0.25

N X_{2}

0.25

; total

1.00 mol

P = \frac{1.00 \times 0.0821 \times 273}{5.0} = 4.4827 \approx 4.48 atm