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JEE Main levelNumerical answerDifficulty 2 of 3ig189

The most probable speed of $CO X_{2}$ molecules (molar mass $44 g mo l^{- 1}$ ) at $500 K$ , taking $R = 8.314 J K^{- 1} mo l^{- 1}$ , in $m s^{- 1}$ (nearest integer) is

Numerical answer type, answer in m/s, tolerance 2.

Answer: 435 m/s

u_{mp} = \frac{2 RT}{M} = \frac{2 \times 8.314 \times 500}{0.044} = 188955 = 434.7 \approx 435 m s^{- 1}

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