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Gaseous State: Ideal Gases
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Kinetic theory of gases and molecular speeds
JEE Advanced level
Single correct option
Difficulty 3 of 3
ig199
The temperature at which the average speed of
O
X
2
(32) equals the rms speed of
H
X
2
(2) at
2
7
∘
C
is (use
π
=
3.14
)
A
5652
K
B
4800
K
C
1884
K
D
2400
K
Answer: A
π
×
32
8
RT
=
2
3
R
×
300
. Squaring:
32
π
8
T
=
450
, so
T
=
8
450
×
32
×
3.14
=
5652
K
.
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