A fixed volume of $He$ (molar mass 4) effuses through a small hole in $40 s$ . The time in seconds (one decimal) for the same volume of $O X_{2}$ (molar mass 32) to effuse under identical conditions is

Numerical answer type, answer in s, tolerance 0.2.

Answer: 113.1 s

For equal volumes,

\frac{t _{O X_{2}}}{t _{He}} = \frac{M _{O X_{2}}}{M _{He}} = 8 = 2.828

t_{O X_{2}} = 40 \times 2.828 = 113.14 \approx 113.1 s