JEE Main levelNumerical answerDifficulty 2 of 3ig027
250mL of hydrogen is collected over water at 27∘C and a total pressure of 740mmHg. The aqueous tension (vapour pressure of water) at 27∘C is 20mmHg. Taking R=0.0821LatmK−1mol−1, the amount of dry hydrogen in millimoles (one decimal) is
Numerical answer type, answer in mmol, tolerance 0.1.
Answer: 9.6 mmol
Pressure of dry HX2=740−20=720mmHg=720/760atm. n=RTPV=0.0821×300(720/760)×0.250=0.00962mol≈9.6mmol.