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JEE Main levelNumerical answerDifficulty 2 of 3ig029

The root mean square speed of $N X_{2}$ molecules (molar mass $28 g mo l^{- 1}$ ) at $300 K$ , taking $R = 8.314 J K^{- 1} mo l^{- 1}$ , in $m s^{- 1}$ (nearest integer) is

Numerical answer type, answer in m/s, tolerance 2.

Answer: 517 m/s

u_{rms} = \frac{3 RT}{M}

with

M

in kg:

\frac{3 \times 8.314 \times 300}{0.028} = 267235.7 = 516.95 \approx 517 m s^{- 1}

.

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