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NEET levelSingle correct optionDifficulty 1 of 3ig006

Under identical conditions of temperature and pressure, the ratio of the rates of diffusion of $He$ (molar mass 4) and $CH X_{4}$ (molar mass 16) is

A $1 : 4$
B $4 : 1$
C $2 : 1$
D $1 : 2$

Answer: C

Graham's law:

\frac{r _{He}}{r _{CH X_{4}}} = \frac{M _{CH X_{4}}}{M _{He}} = \frac{16}{4} = 2

. So the ratio is

2 : 1

; the lighter gas diffuses faster.

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