Answer: A, C
Alcoholic KOH promotes E2 dehydrohalogenation, so 2-bromopropane gives propene and 2-bromo-2-methylbutane gives mainly 2-methylbut-2-ene. Aqueous KOH with bromoethane gives ethanol by substitution. Bromobenzene has no β-hydrogen on an sp3 carbon and does not react.