Chlorobenzene does not give phenol with aqueous $\mathrm{NaOH}$ at room temperature. The best reason is that

1. Athe carbon bearing $\mathrm{Cl}$ is $\mathrm{s}{\mathrm{p}}^3$ and sterically hindered by the ring
2. B$\mathrm{Cl}{}^{-}$ is a stronger base than $\mathrm{OH}{}^{-}$, so it cannot leave
3. Cthe benzene ring is non-polar, so $\mathrm{NaOH}$ cannot dissolve
4. Dthe C-Cl bond has partial double bond character (resonance with the ring, $\mathrm{s}{\mathrm{p}}^2$ carbon) and the phenyl cation is unstable