Answer: A, B, D
SN2 is retarded by steric crowding, giving methyl > primary > secondary. SN1 follows carbocation stability, giving tertiary > secondary > primary. C-I is the weakest carbon-halogen bond and iodide is the best leaving group, so (c) is wrong. Benzyl chloride forms a resonance-stabilised cation yet is also unhindered, while chlorobenzene is inert.