JEE Main levelNumerical answerDifficulty 2 of 3eq126
A 2.50 g sample of impure NaOH (inert impurities, molar mass 40 g/mol) requires 45.0 mL of 1.00 N HCl for complete neutralisation. Find the percentage purity of NaOH by mass (one decimal place).
Numerical answer type, answer in %, tolerance 0.06.
Answer: 72 %
Equivalents of HCl = 1.00 × 0.0450 = 0.0450 = equivalents of NaOH (n = 1). Mass of NaOH = 0.0450 × 40 = 1.80 g. Purity = 1.80/2.50 × 100 = 72.0 %.