A 500 mL solution contains 4.0 g NaOH (40 g/mol) and 3.7 g Ca(OH)2 (74 g/mol). What volume of 0.50 M H2SO4 is required to neutralise 50.0 mL of this solution completely?

JEE Advanced levelSingle correct optionDifficulty 3 of 3eq144

A 500 mL solution contains 4.0 g NaOH (40 g/mol) and 3.7 g $Ca (OH) X_{2}$ (74 g/mol). What volume of 0.50 M $H X_{2} SO X_{4}$ is required to neutralise 50.0 mL of this solution completely?

Equivalents: NaOH = 4.0/40 = 0.100;

Ca (OH) X_{2}

= (3.7/74)

\times

2 = 0.100; total 0.200 eq in 0.500 L, so N = 0.40 N. 50.0 mL contains 20.0 meq. 0.50 M

H X_{2} SO X_{4}

is 1.00 N, so volume = 20.0/1.00 = 20.0 mL.