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JEE Main levelNumerical answerDifficulty 2 of 3eq125

0.630 g of a dibasic acid is exactly neutralised by 20.0 mL of 0.500 M NaOH. Calculate the molar mass of the acid in g/mol (nearest integer).

Numerical answer type, answer in g/mol, tolerance 0.6.

Answer: 126 g/mol

Equivalents of NaOH = 0.500 0.0200 = 0.0100 (n-factor of NaOH = 1). Equivalent mass of acid = 0.630/0.0100 = 63 g/eq. For a dibasic acid, molar mass = equivalent mass 2 = 126 g/mol.
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