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JEE Main levelSingle correct optionDifficulty 2 of 3eq124

4.9 g of $H X_{3} PO X_{4}$ (molar mass 98 g/mol) is dissolved in water to make 250 mL of solution. Its normality for the reaction $H X_{3} PO X_{4} + 2 NaOH Na X_{2} HPO X_{4} + 2 H X_{2} O$ is:

A $0.20 N$
B $0.40 N$
C $0.60 N$
D $0.80 N$

Answer: B

Molarity = (4.9/98)/0.250 = 0.200 M. For this reaction n = 2, and normality = molarity

\times

n = 0.200

\times

2 = 0.40 N.

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