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JEE Main levelSingle correct optionDifficulty 2 of 3eq123

How many equivalents are present in 14.3 g of (molar mass 286 g/mol) when it is titrated with excess HCl to ?

  1. A
  2. B
  3. C
  4. D

Answer: A

Moles = 14.3/286 = 0.0500. Each mole of carbonate takes 2 , so n = 2 and equivalents = moles n = 0.0500 2 = 0.10.
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