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Equivalent mass and n-factor for acids, bases and salts
NEET level
Single correct option
Difficulty 1 of 3
eq114
H
X
3
PO
X
4
(molar mass 98 g/mol) is neutralised by NaOH according to
H
X
3
PO
X
4
+
2
NaOH
Na
X
2
HPO
X
4
+
2
H
X
2
O
. Its equivalent mass in this reaction is:
A
98
g/eq
B
32.67
g/eq
C
196
g/eq
D
49
g/eq
Answer: D
Two protons are replaced per molecule, so n-factor = 2 in this reaction. Equivalent mass = 98/2 = 49 g/eq.
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