JEE Main levelNumerical answerDifficulty 2 of 3eq067
A 0.500g sample containing NaX2CX2OX4 (molar mass 134gmol−1) and inert matter requires 30.0mL of 0.0200MKMnOX4 in hot acidic solution. Calculate the mass percent of NaX2CX2OX4 (one decimal).
Numerical answer type, answer in %, tolerance 0.1.
Answer: 40.2 %
mol KMnO4 = 0.0300 x 0.0200 = 6.00e-4; mol oxalate = 2.5 x 6.00e-4 = 1.500e-03. Mass = 1.500e-03 x 134 = 0.2010 g; percent = 0.2010/0.500 x 100 = 40.20, about 40.2%.