10.0 mL of a hydrogen peroxide solution is titrated in acidic medium with 0.0200 M KMnO4, requiring 18.4 mL (H2O2 is oxidised to O2). The molarity of H2O2 is

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$10.0 mL$ of a hydrogen peroxide solution is titrated in acidic medium with $0.0200 M$ $KMnO X_{4}$ , requiring $18.4 mL$ ( $H X_{2} O X_{2}$ is oxidised to $O X_{2}$ ). The molarity of $H X_{2} O X_{2}$ is

2 MnO4- + 5 H2O2: mol H2O2 = 2.5 x (0.0184 x 0.0200) = 9.200e-04 mol in 10.0 mL. Molarity = 9.200e-04/0.0100 = 0.092 M.