Using the spin-only formula, the ratio mu([FeF6]^3-) / mu([Fe(CN)6]^3-) (high spin for F-, low spin for CN-) is closest to:

JEE Advanced levelSingle correct optionDifficulty 3 of 3cc209

Using the spin-only formula, the ratio $μ ([FeF X_{6}] X^{3 -}) / μ ([Fe (CN) X_{6}] X^{3 -})$ (high spin for $F X^{-}$ , low spin for $CN X^{-}$ ) is closest to:

Both ions contain

Fe X^{3 +}

(

d^{5}

). Fluoride complex:

n = 5

μ = 35 = 5.92

BM. Cyanide complex:

n = 1

μ = 3 = 1.73

BM. Ratio =

5.92/1.73 = 3.42