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NEET levelSingle correct optionDifficulty 1 of 3cc167

Taking $[NiCl X_{4}] X^{2 -}$ to be tetrahedral (weak-field $Cl X^{-}$ ), which statement is correct?

A $s p^{3}$ hybridised and diamagnetic
B $d s p^{2}$ hybridised and diamagnetic
C $s p^{3}$ hybridised and paramagnetic with two unpaired electrons
D $d s p^{2}$ hybridised and paramagnetic with two unpaired electrons

Answer: C

Ni X^{2 +}

is

3 d^{8}

with two unpaired electrons. The weak-field

Cl X^{-}

does not force pairing, so one

4 s

and three

4 p

orbitals hybridise to give

s p^{3}

. Two unpaired electrons remain, so the complex is paramagnetic (

2 \times 4 = 2.83

BM).

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