MolSynapsequestion bank

MolSynapse / Question bank / Coordination Compounds / Valence bond theory: hybridisation and magnetism

NEET levelSingle correct optionDifficulty 1 of 3cc169

$F X^{-}$ is a weak-field ligand, so $[CoF X_{6}] X^{3 -}$ is high spin. The number of unpaired electrons and the hybridisation of $Co$ in this ion are:

A0, $d^{2} s p^{3}$
B4, $s p^{3} d^{2}$
C2, $s p^{3} d^{2}$
D4, $d^{2} s p^{3}$

Answer: B

Co X^{3 +}

is

3 d^{6}

. With a weak-field ligand the electrons are not paired: the configuration is

t_{2 g}^{4} e_{g}^{2}

with four unpaired electrons. The six

F X^{-}

use

4 s

,

4 p

and two

4 d

orbitals, giving

s p^{3} d^{2}

(outer orbital).

Practice Coordination Compounds More on Valence bond theory: hybridisation and magnetism

Previous questionNext question

More questions on Valence bond theory: hybridisation and magnetism