MolSynapsequestion bank

MolSynapse / Question bank / Coordination Compounds / Valence bond theory: hybridisation and magnetism

JEE Main levelSingle correct optionDifficulty 2 of 3cc187

Three of the following species have the same central-atom hybridisation. Which one is the odd one out? (Assume $[Ni (CN) X_{4}] X^{2 -}$ is square planar.)

A $[Ni (CN) X_{4}] X^{2 -}$
B $[NiCl X_{4}] X^{2 -}$
C $Ni (CO) X_{4}$
D $[Zn (NH X_{3}) X_{4}] X^{2 +}$

Answer: A

Ni (CO) X_{4}

,

[NiCl X_{4}] X^{2 -}

and

[Zn (NH X_{3}) X_{4}] X^{2 +}

are tetrahedral with

s p^{3}

.

[Ni (CN) X_{4}] X^{2 -}

is square planar with

d s p^{2}

, so it is the odd one out.

Practice Coordination Compounds More on Valence bond theory: hybridisation and magnetism

Previous questionNext question

More questions on Valence bond theory: hybridisation and magnetism